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  • A bullet of mass , moving with a speed of  penetrates a block of wood of thickness <

A bullet of mass m, moving with a speed of u penetrates a block of wood of thickness x and emerges with a speed v. The force of resistance offered by the wood is given by-

Option: 1

\frac{m}{x}\left(u^2-v^2\right)


Option: 2

\frac{m}{2 x}\left(u^2-v^2\right)


Option: 3

\frac{m}{2 x}\left(v^2-u^2\right)


Option: 4

\frac{m}{x}\left(v^2-u^2\right)


Answers (1)


v^2 =u^2+2 a s \\ v^2-u^2 =2 a s \Rightarrow a=\frac{v^2-u^2}{2 x},
Negative retaridation

{=} \frac{v^2-u^2}{2 x}

\therefore The force of resistance =  \frac{m\left(u^2-v^2\right)}{2 x}

Posted by

Sumit Saini

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