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  • A bus traveling with a speed of 50 km/h can be stopped at a 50 m distance by applying brakes; now the same bus is traveling at 100 km/h; now suppose the bus is skidding then the minimum s

A bus traveling with a speed of 50 km/h can be stopped at a 50 m distance by applying brakes; now the same bus is traveling at 100 km/h; now suppose the bus is skidding then the minimum stopping distance is 

Option: 1

160 m


Option: 2

200 m


Option: 3

230 m

 


Option: 4

300 m 


Answers (1)

best_answer

 let’s use the equation of motion v^{2}=u^{2}-2as

Here v = 0

Therefore s=\frac{u^{2}}{2a}

Let us assume that for the first time velocity is “u” and for the second time it is “U” and the stopping distance for the first is “s” and for the second time is “S”

Therefore

S=\left ( \frac{U}{u}\right )^{2}\times s=\left ( 2 \right )^{2}*50=200\, m

Posted by

Divya Prakash Singh

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