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A car starts from rest and accelerates at 5 $m/s^{2}$ at t=4s a ball is dropped out of a window by a person sitting in the car .what is the velocity and acceleration of the ball at t=6s?

(Take $g=10m/s^{2}$ )
Option: 1
20 $m/s$ ,5 $m/s^{2}$

Option: 2
20 $m/s$ ,0

Option: 3
$20\sqrt{2}m/s,0$

Option: 4
$20\sqrt{2}m/s,10m/s$

Answers (1)

best_answer

$u=0,a=5m/s^{2}$ [ along horizontal direction ]

at $t=4s,V_{x}=U_{x}+a_{x}t$

$V_{x}=20m/s$

Ball when released at $t=4s$ from $t=4s$ to $t=6s$

$V_{y}=0;V_{y}=u_{y}+a_{y}t$

$V_{y}=0+\left ( 10 \right )\left ( 2 \right )=20m/s$

$a=\sqrt{a_{x}^{2}+a_{y}^{2}}$

$=\sqrt{0+\left ( 10 \right )^{2}}=10m/s^{2}$

$v=\sqrt{V_{x}^{2}+V_{y}^{2}}=\sqrt{\left ( 20 \right )^{2}+\left ( 20 \right )^{2}}$

$V=20\sqrt{2}m/s$

Posted by

Sanket Gandhi

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