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A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth where R is the radius of earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is. …………….. hours

Option: 1

7.28


Option: 2

7.68


Option: 3

8.28


Option: 4

8.48


Answers (1)

best_answer

\mathrm{T \propto r^{3 / 2}}

\mathrm{\therefore \frac{T_2}{T_1}=\left(\frac{r_2}{r_1}\right)^{3 / 2}}

\mathrm{\text { or } \quad \begin{aligned} \mathrm{T}_2 & =\left(\frac{r_2}{r_1}\right)^{3 / 2} \mathrm{~T}_1=\left(\frac{3.5 R}{7 R}\right)^{3 / 2}(24) \mathrm{h} \\ & =8.48 \mathrm{~h} \end{aligned}}

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Devendra Khairwa

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