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  • A juggler throws balls into the air. He throws one whenever the previous one is at its highest point. If he throws n balls each second, the height to which each ball will rise is,  <

A juggler throws balls into the air. He throws one whenever the previous one is at its highest point. If he throws n balls each second, the height to which each ball will rise is,

 

Option: 1

\frac{g}{2{{n}^{2}}}


Option: 2

\frac{2g}{{{n}^{2}}}


Option: 3

\frac{2g}{n}


Option: 4

\frac{g}{4{{n}^{2}}}


Answers (1)

Time taken by each ball to reach highest point,

t=\frac{1}{n} second 

As the juggler throws the second ball, when the first ball is at its highest point, so v=0

Using v=u+at we have 

\\0=u+(-g)(\frac{1}{n}) \\ \\u=\frac{g}{n}

Also, {{v}^{2}}={{u}^{2}}+2as

\therefore 0=\left( \frac{g}{{{n}^{2}}} \right)+2(-g)h

h=\frac{g}{2{{n}^{2}}}

Posted by

Ramraj Saini

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