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  • A mass m moves in a circle on a smooth horizontal plane with velocity v0 at a radius R0. The mass is attached to a string which passes through a smooth hole in the plane as sh

A mass m moves in a circle on a smooth horizontal plane with velocity v0 at a radius R0. The mass is attached to a string which passes through a smooth hole in the plane as shown.

The tension in the string is increased gradually and finally m moves in a circle of radius \frac{R_0}{2}. The final value of the kinetic energy is:

Option: 1

mv_0^{2}


Option: 2

\frac{1}{4}mv_0^{2}


Option: 3

2mv_0^{2}


Option: 4

\frac{1}{2}mv_0^{2}


Answers (1)

Use conservation of Angular Momentum Li=Lf

mV_{o}R_{o}=m{V}'(R_{o}/2)=V{}'=2V_{o}\\ K_{f}=\frac{1}{2}mv{}'^{2}=\frac{1}{2}m(2V_{o})^{2}=2mv_{o}^{2}

Posted by

Ramraj Saini

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