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  • A mass of 10 gram moving horizontal with a velocity of 100 cm/sec strikes a pendulum bob of mass 10 gram. The two masser stick together. The maximum height reached by the system now is , (<img alt=

A mass of 10 gram moving horizontal with a velocity of 100 cm/sec strikes a pendulum bob of mass 10 gram. The two masser stick together. The maximum height reached by the system now is , (g=m/s^{^{2}})

 

Option: 1

1.25 cm


Option: 2

5 cm


Option: 3

2.5 cm


Option: 4

zero


Answers (1)

best_answer

Kinetic energy of mass \mathrm{\begin{aligned} & =\frac{1}{2} m v^2 \\ & =\frac{1}{2}(10)(100)^2 \mathrm{erg} . \\ & =5 \times 10^4 \mathrm{erg} . \end{aligned}}

This mass sticker the bob and sticks to it.

The two together now more onwards to rise to certain height and gain potential energy.

Potential energy of (mass+bob)=(mass)x g x h

                                                 =\mathrm{(10+10)}\times 10^{3}h

\therefore Potential energy = kinetic energy

\mathrm{\begin{aligned} 20 \times 10^3 \times L= & 5 \times 10^4 \\ h & =\frac{5 \times 10^4}{20 \times 10^3}=\frac{1}{4} \times 10=2.5 \mathrm{~cm} . \end{aligned}}

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sudhir kumar

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