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  • A particle of mass moves in circular path of radius n

A particle of mass m moves in circular path of radius r with centripetal acceleration at any time t is given as a_{c}=kt , the power of resultant force is -

Option: 1

\frac{mkr}{2}


Option: 2

\frac{m\sqrt{kr}}{2}


Option: 3

\frac{m\left ( kr \right )^{3/2}}{2}


Option: 4

\frac{kr}{2}


Answers (1)

best_answer

Given, \quad a_c=k t \\\ \begin{aligned} & \frac{v^2}{r}=k t \\ & v=\sqrt{k r t} \end{aligned} \\\ kinetic\ energy\ k \cdot E \cdot=\frac{1}{2} m k^2=\frac{1}{2} m k r t \\\\ \text { power }=\frac{d k}{d t}=\frac{d}{d t}\left(\frac{m k r}{2} t\right) \Rightarrow \text { power }=\frac{1}{2} m k r

Posted by

Kuldeep Maurya

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