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  • A satellite close to earth is in orbit above the equator with a period of rotation of 1.5 hrs. If it is above a point P on the equator at some time, it will be above P again after time<div clas

A satellite close to earth is in orbit above the equator with a period of rotation of 1.5 hrs. If it is above a point P on the equator at some time, it will be above P again after time

Option: 1

1.5 hrs


Option: 2

1.6 hrs. if it is rotating from west to east.


Option: 3

24/17 hrs. if it is rotating from west to east.


Option: 4

24/17 hrs. if it is rotating from east to west.


Answers (1)

best_answer

Let \omega_0 = the angular velocity of earth above its axis \mathrm{=\frac{2 \pi}{24} \mathrm{rad} / \mathrm{hr}}

Let \omega = angular velocity, of satellite\mathrm{=\frac{2 \pi}{1.5}}

For a satellite rotating from west to east. (same as earth), the relative angular velocity

\mathrm{\omega_1=\omega-\omega_0}

Time period of rotation relative to earth \mathrm{=\frac{2 \pi}{\omega_1}=1.6 \mathrm{~h}}

Now for a satellite rotating from east to west (opposite to earth) the relative angular velocity \mathrm{\omega_2=\omega+\omega_0}

Time period of rotation relative to earth \mathrm{=\frac{2 \pi}{\omega_2}=\frac{24}{17} \mathrm{hrs} .}

Hence (D) is correct.

Posted by

Irshad Anwar

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