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A satellite of the sun is in circular orbit around the sun, midway between the sun and the earth. Then
 

Option: 1

The acceleration of the satellite is four times the acceleration of the earth
 


Option: 2

The period of the satellite is nearly 129 days


Option: 3

The speed of the satellite equals the escape velocity of earth
 


Option: 4

All of the above


Answers (1)

best_answer

\mathrm{ \frac{\mathrm{T}_{\mathrm{s}}^2}{\mathrm{~T}_{\mathrm{e}}^2}=\frac{\left(\frac{\mathrm{a}}{2}\right)^3}{(\mathrm{a})^3}=\frac{1}{8} ; \frac{\mathrm{T}_{\mathrm{s}}}{\mathrm{T}_{\mathrm{e}}}=\frac{1}{\sqrt{8}} }

\mathrm{ \mathrm{~T}_{\mathrm{s}}=\frac{\mathrm{T}_{\mathrm{e}}}{\sqrt{8}}=\frac{365}{2 \sqrt{2}}=129 \text { days } }

Hence option 4 is correct.
 

Posted by

Irshad Anwar

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