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  • A spherical planet for out in space has a mass and diameter <img alt="\mathrm{D_0}" src="https://

A spherical planet for out in space has a mass \mathrm{M_0} and diameter \mathrm{D_0}. A particle of mass \mathrm{m} falling freely near the surface of this planet will experience an acceleration due to gravity which is equal to
 

Option: 1

\mathrm{\frac{\mathrm{GM}_0}{\mathrm{D}_0^2}}


 


Option: 2

\mathrm{\frac{4 \mathrm{GmM}_0}{\mathrm{D}_0^2}}
 


Option: 3

\mathrm{\frac{4 \mathrm{GM}_0}{\mathrm{D}_0^2}}
 


Option: 4

\mathrm{\frac{\mathrm{GmM}}{\mathrm{D}_0^2}}


Answers (1)

best_answer

Let \mathrm{g}_{\mathrm{o}} to the acceleration thin \mathrm{\mathrm{mg}_{\mathrm{o}}=\frac{\mathrm{GM}_{\mathrm{o}} \mathrm{m}}{\left(\frac{\mathrm{D}_{\mathrm{o}}}{2}\right)^2}}

\mathrm{ \mathrm{g}_{\mathrm{o}}=\frac{4 \mathrm{GM}_{\mathrm{o}}}{\mathrm{D}_{\mathrm{o}}{ }^2} }

Hence option 3 is correct.
 

Posted by

Rakesh

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