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A stone falls freely under the effect of gravity. It covers the distances   h_{1,}\, h_{2}\, and\, h_{3}of the first 5 seconds, the last 5 seconds,and the last 5 seconds, respectively. The relation between:

Option: 1

h_1=h_2=h_3


Option: 2

h_1=2h_2=3h_3


Option: 3

h_1=\frac{h_2}{3}=\frac{h_3}{5}


Option: 4

h_2=3h_1\ and\ h_3=3h_2


Answers (1)

best_answer

h_1=\frac{1}{2}g\left(5\right)^2

And h_2=\frac{1}{2}g\left(10\right)^2-\frac{1}{2}g\left(5\right)^2

And the value of last 5 seconds that is  h_3 , we get:

h_3=\frac{1}{2}g\left(15\right)^2-\frac{1}{2}g\left(10\right)^2

Therefore, h_1=\frac{h_2}{3}=\frac{h_3}{5}

Posted by

Ritika Kankaria

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