Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

At 100^oC the K_{w} of water is 55 times its value at 25^\circC. What will be the pH of neutral solution? (log 55=1.74)

Option: 1

6.13


Option: 2

7.00


Option: 3

7.87


Option: 4

5.13


Answers (1)

best_answer

Pure water is always neutral, at different temperatures the pH scale can change but water is always neutral. 
On an increase of temperature range of the pH scale decreases. 

H_2O \rightleftharpoons H^++OH^-

At 25^oC

K_w=[H^+][OH^-]=10^{-14}

At 100^oC

K_w=[H^+][OH^-]=55 \times10^{-14}

pK_w=-log(55 \times 10^{-14})=12.26\\ pH=\frac{12.26}{2}=6.13

the COrrect answer is option 1.

Posted by

Ajit Kumar Dubey

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Himachal Pradesh CM announces hike in monthly stipend of resident doctors
anam-khan

Karnataka AYUSH UG 2025: Round 3 stray vacancy registration begins; option entry ends in two days
anam-khan

Maharashtra NEET UG 2025: Just 114 marks enough for private MBBS seat; govt colleges close at 500

Latest Question