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  • Displacement equation is given by  <img alt="\mathrm{s=2 A \cos t+B \sin t}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7Bs%3D2%20A%20%5Ccos%20t&plus;B%20%5Csin%20t%7D"

Displacement equation is given by  \mathrm{s=2 A \cos t+B \sin t}
Acceleration at \mathrm{t=\pi / 2} will be-

Option: 1

\mathrm{-B}


Option: 2

\mathrm{B}


Option: 3

\mathrm{B^2}


Option: 4

\mathrm{-2B}


Answers (1)

best_answer

Given, \mathrm{\quad s=2 A \cos t+B \sin t}

Velocity \mathrm{=\frac{d s}{d t}=v=-2 A \sin t+B \cos t }

Acceleration \mathrm{=\frac{d^2 s}{d t^2}=a=-2 A \cos t-B \sin t}

 

\mathrm{\text { At } t \rightarrow \pi / 2 \text { acceleration }(a)=-2 A \cos \pi / 2-B \sin \pi / 2}

                                                              \mathrm{=-2 A \times 0-B \times 1}

                                                               \mathrm{a=-B \mathrm{~m} / \mathrm{s}^2}

 

Posted by

Pankaj Sanodiya

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