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  • Displacement of any moving particle is give by the relation - <img alt="s=v_0 t+\frac{1}{2} a t^2," src="https://entrancecorner.oncodecogs.com/gif.latex?s%3Dv_0%20t&plus;%5Cfrac%7B1%7D%7

Displacement of any moving particle is give by the relation -
s=v_0 t+\frac{1}{2} a t^2,  where  v_0  is initial velocity. The value of Rate of charge of displacement -

Option: 1

v_0+2 a t


Option: 2

\quad v_0+\frac{a t}{2}


Option: 3

V_0 t


Option: 4

v_0+a t


Answers (1)

best_answer

Given,

displacement (s)=v_0 t+\frac{1}{2} a t^2

Rate of change of displacement   \frac{d s}{d t}=velocity


\frac{d s}{d t}=\frac{d}{d t}\left[v_0 t+\frac{1}{2} a t^2\right] \\
\frac{d s}{d t}=v_0+\frac{1}{2} a \times 2 t^{\prime}=v_0+a t \\
\frac{d s}{d t}=v_0+a t

Posted by

Shailly goel

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