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  • For a projectile, the ratio of maximum height reached to the square of flight time is <img alt="\mathrm{ \left(g=10 \mathrm{~m} / \mathrm{s}^2\right)}" src="https://entrancecorner.oncodecogs.c

For a projectile, the ratio of maximum height reached to the square of flight time is \mathrm{ \left(g=10 \mathrm{~m} / \mathrm{s}^2\right)}
 

Option: 1

5: 4


Option: 2

5: 2


Option: 3

5: 1


Option: 4

10: 1


Answers (1)

best_answer

 Maximum height (H ) 
\mathrm{=\frac{u^2 \sin ^2 \theta}{2 g}} \\
 Flight time (T)
\mathrm{=\frac{2 u \sin \theta}{g}}
Ratio of maximum height reached to the square of flight time - 
\mathrm{\begin{aligned} & \frac{H}{T^2}=\frac{u^2 \sin ^2 \theta}{2 g} \times \frac{g^2}{4 u^2 \sin ^2 \theta} \\ & \frac{H}{T^2}=\frac{g}{8}=\frac{10}{8} \\ & \frac{H}{T^2}=\frac{5}{4} \text { Ans. } \end{aligned}}

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HARSH KANKARIA

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