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  • If the velocity of a particle is   then the

If the velocity of a particle is  (15+3t^{2})ms^{-1}; then the average acceleration of the particle between 3 sec and 5 sec is: 

Option: 1

15\: ms^{-2}


Option: 2

24\: ms^{-2}


Option: 3

35\: ms^{-2}


Option: 4

45\: ms^{-2}


Answers (1)

best_answer

Velocity at 3 sec  = (15+3*3^{2})=42\: ms^{-1}

Velocity at 5 sec  = (15+3*5^{2})=90\: ms^{-1}
Then the avg acceleration = \frac{90-42}{5-3}=24\: ms^{-2}

Posted by

sudhir kumar

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