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In the above figure

Component of Displacement along y or perpendicular to the inclined plane is

Option: 1

 S_{y} = U_{y}t + \frac{1}{2}a_{y}.t^{2}

where a_{y} = -gcos\beta and U_{y} = USin\theta


Option: 2

 S_{y} = U_{y}t + \frac{1}{2}a_{y}.t^{2}

where a_{y} = -gcos\beta and U_{y} = 2USin\theta


Option: 3

 S_{y} = U_{y}t + \frac{1}{2}a_{y}.t^{2}

where a_{y} = -gcos\beta and U_{y} = 5USin\theta


Option: 4

 S_{y} = U_{y}t + \frac{1}{2}a_{y}.t^{2}

where a_{y} = -3gcos\beta and U_{y} = USin\theta


Answers (1)

best_answer

 S_{y} = U_{y}t + \frac{1}{2}a_{y}.t^{2}

where a_{y} = -gcos\beta and U_{y} = USin\theta

Posted by

Irshad Anwar

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