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In the above figure

Component of Displacement along x or along inclined plane is 

Option: 1

 S_{x} = U_{x}t + \frac{1}{2}a_{x}.t^{2}

where U_{x} = Ucos\theta and U_{y} = USin\theta


Option: 2

 S_{x} = U_{x}t + \frac{1}{2}a_{x}.t^{2}

where U_{x} = Ucos\theta and a_{x} = -gsin\beta


Option: 3

 S_{x} = 2U_{x}t + \frac{1}{2}a_{x}.t^{2}

where U_{x} = Ucos\theta and a_{x} = -gsin\beta


Option: 4

 S_{x} = U_{x}t + \frac{1}{2}a_{x}.t^{2}

where U_{x} = Ucos2\theta and  a_{x} = -gsin\beta


Answers (1)

best_answer

 S_{x} = U_{x}t + \frac{1}{2}a_{x}.t^{2}

where U_{x} = Ucos\theta and a_{x} = -gsin\beta

Posted by

Divya Prakash Singh

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