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  • Motion of the ball with respect to time is given by- <img alt="\mathrm{s_0=v_0 t+\frac{1}{2} a t^2, V_0=\alpha t^2, a=\beta t^4}" src="/latex-image/?%5Cmathrm%7Bs_0%3Dv_0%20t&plus;%5C

Motion of the ball with respect to time is given by-

\mathrm{s_0=v_0 t+\frac{1}{2} a t^2, V_0=\alpha t^2, a=\beta t^4}

Where So, \mathrm{V_0}  and a are a is displacement, velocity and Acceleration.I consider a= \alpha +\beta t^{4} what will be displacement in another form is proportional to -

 

Option: 1

\mathrm{t^{4}}


Option: 2

\mathrm{t^{5}}


Option: 3

\mathrm{t^{2}}


Option: 4

\mathrm{t^{6}}


Answers (1)

best_answer

Acceleration (a) \mathrm{=Bt^{4}}

\text{velocity(v)}\mathrm={\int adt}

\mathrm{\begin{aligned} & =\int \beta t^4 d t \\ & =\beta \frac{t^5}{5} \end{aligned}}

Now, Displacement can be written as \mathrm{\int udt}

\mathrm{\begin{aligned} \operatorname{Displacement} \(s) & =\int \frac{\beta t^5}{5} \\ & =\frac{\beta t^6}{30} \end{aligned}}

 

Posted by

Ritika Harsh

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