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  • Position of two particles A and B as a function of time are given by <img alt="\mathrm{X_A=-3 t^2+8 t}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BX_A%3D-3%20t%5E2&pl

Position of two particles A and B as a function of time are given by \mathrm{X_A=-3 t^2+8 t}, \mathrm{Y_B=10-8 t^3}, The ratio \mathrm{\frac{x_B}{x_A}} in the form of velocity will be at t=1 sec 

Option: 1

3


Option: 2

1


Option: 3

4


Option: 4

5


Answers (1)

best_answer

Case I-             \mathrm{x_A=-3 t^2+8 t}

    \mathrm{velocity \frac{d x_A}{d t}=-6 t} ----------(1)

Case II -         \mathrm{y_B=10-8 t^3}

\mathrm{\text { Velocity } \begin{aligned} \frac{d y_B}{d t} & =-8 \times 3 t^2 \\ & =-24 t^2 \end{aligned}}

Now, \mathrm{\frac{X_B}{x_A}} in the velocity form \mathrm{\begin{aligned} & =-\frac{24 t^2}{-6 t} \\ & =4 t \end{aligned}}

At t=1 sec will be 4

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Gaurav

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