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  • Position of two particles A and B as a function of time are given by - <img alt="\mathrm{X_A =-3 t^2+8 t+\alpha }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmath

Position of two particles A and B as a function of time are given by -
\mathrm{X_A =-3 t^2+8 t+\alpha }

&  \mathrm{ Y_B =10-8 t^3 }
Ratio \mathrm{\frac{d^2 X_A / d t^2}{d^2 Y_B / d t^2}} will be-

Option: 1

\mathrm{\frac{-1}{8t}}


Option: 2

\mathrm{\frac{1}{6t}}


Option: 3

\mathrm{\frac{1}{8t}}


Option: 4

\mathrm{{-8t}}


Answers (1)

\mathrm{X_A =-3 t^2+8 t+\alpha }

\mathrm{\frac{d X_A}{d t} =-6 t+8}

\mathrm{\frac{d^2 X_A}{d t^2} =-6}     .....(1)

 

\mathrm{Y_B=10-8 t^3 }

\mathrm{\frac{d Y_B}{d t}=-24 t^2}

\mathrm{\frac{d^2 Y_B}{d t^2}=-48 t}    .....(2)

 

Ratio   \mathrm{ \frac{d^2 X_A / d t^2}{d^2 Y_B / d t^2}=\frac{-6}{-48 t}=\frac{1}{8 t}}

Posted by

Ramraj Saini

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