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  • The acceleration due to gravity on the planet is 9 times the acceleration due to gravity on planet <i

The acceleration due to gravity on the planet \mathrm{A} is 9 times the acceleration due to gravity on planet \mathrm{B}. A man jumps to a height of \mathrm{2 \mathrm{~m}} on the surface of \mathrm{A}. what is the height of jump by the same person on the planet \mathrm{B} ?
 

Option: 1

6 \mathrm{~m}


 


Option: 2

\frac{2}{3} \mathrm{~m}
 


Option: 3

\frac{2}{9} \mathrm{~m}
 


Option: 4

18 \mathrm{~m}


Answers (1)

best_answer

\mathrm{g}_{\mathrm{A}}=9 \mathrm{~g}_{\mathrm{B}}, \frac{\mathrm{g}_{\mathrm{A}}}{\mathrm{g}_{\mathrm{B}}}=9
on planet A, In jumping the man goes up to height \mathrm{\mathrm{h}_{\mathrm{A}}=2 \mathrm{~m}}

\mathrm{\therefore \quad PE} gained by him is \mathrm{\mathrm{mg}_{\mathrm{A}} \mathrm{h}_{\mathrm{A}}}

Same amount of work is done by jumping on planet B

\mathrm{\therefore P.E.} gained by him on planet \mathrm{\mathrm{mg}_B \mathrm{~h}_B \:}

 equating, \mathrm{\mathrm{mg}_{\mathrm{A}} \mathrm{h}_{\mathrm{A}}=\mathrm{mg}_{\mathrm{B}} \mathrm{h}_{\mathrm{B}}}

\mathrm{\mathrm{g}_{\mathrm{A}} \mathrm{h}_{\mathrm{A}}=\mathrm{g}_{\mathrm{B}} \mathrm{h}_{\mathrm{B}}}

\mathrm{\mathrm{h}_{\mathrm{B}}=\frac{\mathrm{g}_{\mathrm{A}}}{\mathrm{g}_{\mathrm{B}}} \mathrm{h}_{\mathrm{A}}=9 \times 2=18 \mathrm{~m} }

\mathrm{\left [ \because \frac{g_A}{g_B} =9\right ]}

Hence option 4 is correct.


 

Posted by

Anam Khan

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