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The correct order of acidic strength is 

Option: 1

\mathrm{H}_2 \mathrm{O}>\mathrm{D}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{O}_2


Option: 2

\mathrm{D}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{O}<\mathrm{H}_2 \mathrm{O}_2


Option: 3

\mathrm{D}_2 \mathrm{O}<\mathrm{H}_2 \mathrm{O}<\mathrm{H}_2 \mathrm{O}_2


Option: 4

\mathrm{H}_2 \mathrm{O}=\mathrm{D}_2 \mathrm{O}=\mathrm{H}_2 \mathrm{O}_2


Answers (1)

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  • \mathrm{H}_2 \mathrm{O}_2  gives 2 hydrogen ions in aqueous solution whereas water gives 1 hydrogen ion. As \mathrm{H}_2 \mathrm{O}_2 protonates to a larger extent than water in aqueous solution, hence, it has a larger Ka(acid dissociation constant), thus making it a stronger Bronsted-Lowry acid than water.

 

  • In between \mathrm{H}_2 \mathrm{O} and \mathrm{D}_2 \mathrm{O}, The reason for this is that the atoms in the molecules keep vibrating and the bonds of H being slightly weaker than D are easily delocalised. (due to heavier weight of D than H, the vibrations are weaker and thus the bonds are stable). Hence \mathrm{H}_2 \mathrm{O} is slightly acidic than \mathrm{D}_2 \mathrm{O} 

 

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Divya Prakash Singh

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