Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • The gravitational field due to a mass distribution is given by <img alt="\mathrm{I=\left(A / x^3\right)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BI%3D%5Cleft%28A%20/%2

The gravitational field due to a mass distribution is given by \mathrm{I=\left(A / x^3\right)}  in X−direction. The gravitational potential at a distance x is equal to

Option: 1

\mathrm{-\frac{A}{x^3}}


Option: 2

\mathrm{-\frac{A}{2 x^2}}


Option: 3

\mathrm{-\frac{A}{ x^4}}


Option: 4

\mathrm{\frac{A}{2 x^2}}


Answers (1)

best_answer

The potential at a distance x is

\mathrm{\begin{aligned} & V(x)=-\int_{\infty}^x I d x=-\int_{\infty}^x \frac{A}{x^3} d x \\ & V(x)=\left[\frac{A}{2 x^2}\right]_{\infty}^x=\frac{A}{2 x^2} \end{aligned}}

Therefore (D).

Posted by

Ajit Kumar Dubey

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 LIVE: NTA to open registrations at neet.nta.nic.in shortly; 1.29 lakh MBBS seats in India
anam-khan

Rabri Devi accuses Bihar govt of 'covering up' facts in NEET aspirant death case
anam-khan

NEET UG 2026 Registration LIVE: NTA to begin NEET form soon at neet.nta.nic.in; exam date, fees updates

Latest Question