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  • The gravitational field due to a mass distribution is given by <img alt="\mathrm{I=\left(A / x^3\right)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BI%3D%5Cleft%28A%20/%2

The gravitational field due to a mass distribution is given by \mathrm{I=\left(A / x^3\right)}  in X−direction. The gravitational potential at a distance x is equal to

Option: 1

\mathrm{-\frac{A}{x^3}}


Option: 2

\mathrm{-\frac{A}{2 x^2}}


Option: 3

\mathrm{-\frac{A}{ x^4}}


Option: 4

\mathrm{\frac{A}{2 x^2}}


Answers (1)

best_answer

The potential at a distance x is

\mathrm{\begin{aligned} & V(x)=-\int_{\infty}^x I d x=-\int_{\infty}^x \frac{A}{x^3} d x \\ & V(x)=\left[\frac{A}{2 x^2}\right]_{\infty}^x=\frac{A}{2 x^2} \end{aligned}}

Therefore (D).

Posted by

Ajit Kumar Dubey

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