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  • The height  and the distance  along the horiz

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y=\left ( 8t -5t^{2} \right ) meter and x= 6t meter, where t is in second. The velocity with which the projectile is projected is

Option: 1

8m/s


Option: 2

6m/s


Option: 3

10m/s


Option: 4

None of these


Answers (1)

best_answer

V_y=\frac{d y}{d t}=8-10 t, \quad V_x=\frac{d x}{d t}=6 \\\\ at \ the\ time\ of\ projection\ V_y=\frac{d y}{d t}=8\ and\ V_x=6 \\\
\begin{aligned} \therefore \quad v=\sqrt{V_x^2+V_y^2} & =\sqrt{6^2+8^2} \\ & =\sqrt{100}=10 \mathrm{~m} / \mathrm{s} . \end{aligned}

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Ritika Jonwal

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