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  • The period of rotation of the earth so as to make any object weight−less on its equator isOption: 1 84 min<div class='qna-option'

The period of rotation of the earth so as to make any object weight−less on its equator is

Option: 1

84 min


Option: 2

74 minutes


Option: 3

64 minutes


Option: 4

54 minutes


Answers (1)

best_answer

Put \mathrm{\mathrm{g}_{\mathrm{e}}=0}, in the expression

\mathrm{\begin{aligned} & \mathrm{g}_{\mathrm{e}}=\mathrm{g}_0-\mathrm{r} \omega^2 \quad \Rightarrow \quad \omega=\sqrt{\frac{\mathrm{g}_0}{\mathrm{r}}} \\ & \Rightarrow \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{r}}{\mathrm{g}_0}}, \end{aligned}}

\mathrm{\text { putting } \mathrm{r}=6.4 \times 10^6 \mathrm{~m} \text { and } \mathrm{g}_0=9.8 \mathrm{~m} / \mathrm{sec}^2 \text {, we obtain, } \mathrm{T}=84 \mathrm{~min}}

Therefore (A)

Posted by

SANGALDEEP SINGH

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