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  • The position  (in meters) of a particle on the <img alt="x" src="https://entrancecorner.oncodecogs.com/gif.latex?x"

The position x (in meters) of a particle on the x -axis is given by-

x=5 t^3+3 t^2-9
where t is the time in seconds. What is the acceleration of the particle at  t=2 seconds \left(\right.$ in $\mathrm{m} / \mathrm{s}^2 )

Option: 1

31


Option: 2

66


Option: 3

29


Option: 4

75


Answers (1)

best_answer

Given, x=5 t^3+3 t^2-9
velocity  V=\frac{d x}{d t}=15 t^2+6 t
Acceleration  a=\frac{d^2 x}{d t^2}=30 t+6

a=\left.\frac{d^2 x}{d t^2}\right|_{t=2 \mathrm{sec}} =60+6 \\


 =66 \mathrm{~m} / \mathrm{s}^2 

Posted by

SANGALDEEP SINGH

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