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The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be
 

Option: 1

\mathrm{83\: minutes}



 


Option: 2

\mathrm{83 \times \sqrt{8} \: minutes}
 


Option: 3

\mathrm{664 \: minutes}
 


Option: 4

\mathrm{249 \: minutes}


Answers (1)

best_answer

\mathrm{T}^2=\mathrm{kR} ; \mathrm{T}^2=\mathrm{k}(4 \mathrm{R})^3

\frac{\mathrm{T}^{\prime 2}}{\mathrm{~T}^2}=64, \mathrm{~T}^{\prime}=8 \mathrm{~T}=8 \times 83=664 \mathrm{~min} .

Hence option 3 is correct.
 

Posted by

rishi.raj

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