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The work done by gravity of earth in maintaining a satellite in its orbit is

where M, m are masses of earth and satellite and r = radius of the orbit.

Option: 1

0


Option: 2

>0


Option: 3

\mathrm{\frac{\pi G M m}{r}}


Option: 4

\mathrm{-\frac{G M m}{2 r}}


Answers (1)

best_answer

Since, the earth satellite is moving in circular orbit, the gravitational force of earth \overrightarrow{\mathrm{F}}_{\mathrm{gr}} and the displacement \overrightarrow{\mathrm{d} s} of the satellite are mutually perpendicular.

{\mathrm{\Rightarrow \text { Work done by gravity }=\mathrm{W}_{\mathrm{gr}}=\int \overrightarrow{\mathrm{F}}_{\mathrm{gr}} \overrightarrow{\mathrm{d}} \mathrm{s}}

{\mathrm{=\int \mathrm{F}_{\mathrm{g}} \mathrm{ds} \cos 90^{\circ}=0 .}

Hence, (A) is correct.

Posted by

Irshad Anwar

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