Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The x position of a particle on the x-axis with respect to time t is given by

$x=9t^3-t^2$ where x is in meters and t is in seconds.The value of acceleration (in m/s²) at t=1 sec is
Option: 1
12

Option: 2
52

Option: 3
30

Option: 4
50

Answers (1)

best_answer

$\\ x=9t^3-t^2 \\ v=\frac{dx}{dt}=27t^2-2t \\ a=\frac{dv}{dt}=54t-2$

at t=1 sec

a=52 m/s²

Posted by

Divya Prakash Singh

View full answer

NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NTA declares NEET UG result 2025 withheld after MP HC orders over power outage during exam

anam-khan

MCC NEET UG counselling 2025 registration from July 21 for MBBS, BDS, AYUSH admissions

anam-khan

From 589 to 41: NEET candidate misses cut-off over silly error, HC orders re-checking of OMR sheet

Latest Question