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The x position of a particle on the x-axis with respect to time t is given by

$x=9t^3-t^2$ where x is in meters and t is in seconds.The value of acceleration (in m/s²) at t=1 sec is
Option: 1
12

Option: 2
52

Option: 3
30

Option: 4
50

Answers (1)

best_answer

$\\ x=9t^3-t^2 \\ v=\frac{dx}{dt}=27t^2-2t \\ a=\frac{dv}{dt}=54t-2$

at t=1 sec

a=52 m/s²

Posted by

Divya Prakash Singh

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