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Two particle projected at 60^{\circ} and 45^{\circ} with the vertically with the same speed. find the ratio of maximum height attained by two projectile particle.

Option: 1

\mathrm{\frac{3}{2}}


Option: 2

\mathrm{\frac{1}{2}}


Option: 3

\mathrm{\frac{5}{2}}


Option: 4

None of these


Answers (1)

best_answer

angle with horizontal are \mathrm{30\degree} and \mathrm{45\degree} 

\mathrm{\begin{aligned} & H_1=\frac{u^2 \sin ^2 30}{2 g} \\ & H_2=\frac{(4)^2 \sin ^2 45^{\circ}}{2 g} \\ & \frac{H_1}{H_2}=\frac{1}{2} \end{aligned}}

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Pankaj

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