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Two satellites \mathrm{S_1\: and \: S_2} revolve round a planet in coplanar circular orbits in the same sense. Their periods of revolution are 1 hour and 8 hour respectively. The radius of the orbit of \mathrm{S_1 \: is\: 10^4 \mathrm{~km}}., the angular speed of \mathrm{S_2}  as observed by an astronaut in \mathrm{S_1} is
 

Option: 1

\frac{\pi}{2}

 


Option: 2

\frac{\pi}{3}
 


Option: 3

\frac{\pi}{4}
 


Option: 4

\frac{\pi}{6}


Answers (1)

best_answer

\mathrm{\omega=\left|\frac{v_2-v_1}{r_2-r_1}\right|}

\mathrm{ \Rightarrow \omega=\left|\frac{10^4 \mathrm{~m}}{3 \times 10^4}\right| }

\mathrm{ \Rightarrow \omega=\frac{\pi}{3} \mathrm{rads}^{-1} }

Hence option 2 is correct.



 

Posted by

Rakesh

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