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  •  When a body is projected with speed 25 m/sec at angle  with the horizontal, so that range & it

 When a body is projected with speed 25 m/sec at angle \theta with the horizontal, so that range & its maximum height are equal than final the value of \mathrm {tan\; \theta }.

Option: 1

\mathrm{\frac{1}{4}}


Option: 2

\mathrm{4}


Option: 3

\mathrm{\frac{1}{2}}


Option: 4

\mathrm{\frac{\sqrt{3}}{2}}


Answers (1)

best_answer

\mathrm{\begin{aligned} & R=\frac{2 u^2 \sin \theta \cdot \cos u}{g} \text { (Range) } \\ & H=\frac{u^2 \sin ^2 \theta}{a} \quad (H_{max})\end{aligned}}

\mathrm{\begin{aligned} &\begin{aligned} & \frac{\text { range }}{\text { reight }}=\frac{2 x^2 \sin \theta \cdot \cos \theta}{g} \\ & \frac{y^2 \sin ^2 \theta}{2 g} \\ & 1=4 \frac{\cos \theta}{\sin \theta} . \\ & \end{aligned}\\ \tan \theta=4 \end{aligned}}

Posted by

Gautam harsolia

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