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  • when a stone is thrown up, it reaches maximum height h travelling in the last second

when a stone is thrown up, it reaches maximum height h travelling 50 \mathrm{~m} in the last second, the velocity with which the ball should be thrown up-

Option: 1

55 m/s


Option: 2

20 m/s


Option: 3

40 m/s


Option: 4

15 m/s


Answers (1)

best_answer

We know that - 

\mathrm{\begin{aligned} S_n & =\frac{1}{2} g(2 t-1) \\ 50 & =\frac{1}{2} \times 10(2 t-1) \\ 100 & =10(2 t-1) \\ 10 & =2 t-1 \\ t & =11 / 2 \mathrm{sec} \end{aligned}}

Use Newton's equation of motion 

\mathrm{ \begin{aligned} v & =g \cdot t \\ & =10 \times \frac{11}{2} \\ v & =55 \mathrm{~m} / \mathrm{s} \end{aligned} }Ans.

Posted by

Pankaj

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