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Which among the following is correct order with respect to the thermal stability of metal hydrides?

Option: 1

\mathrm{CsH}>\mathrm{RbH}>\mathrm{KH}>\mathrm{NaH}>\mathrm{LiH}


Option: 2

\mathrm{LiH}>\mathrm{NaH}>\mathrm{KH}>\mathrm{RbH}>\mathrm{CsH}


Option: 3

\mathrm{LiH}>\mathrm{KH}>\mathrm{NaH}>\mathrm{CsH}>\mathrm{RbH}


Option: 4

\mathrm{NaH}>\mathrm{LiH}>\mathrm{KH}>\mathrm{RbH}>\mathrm{CsH}


Answers (1)

Hydrides are thermally stable when the size of cation and anion are in the same order. Smaller anions forms stable compound with smaller cations.

The thermal stability of the hydrides decrease down the groups since the size of the cation increase down the group. Hence, the decreasing order of thermal stability of group IA hydride is \mathrm{LiH}>\mathrm{NaH}>\mathrm{KH}>\mathrm{RbH}>\mathrm{CsH}.

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Kshitij

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