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8.(i)    A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ?

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Total number of balls in the bag = 8
No. of red balls = 3
No. of black balls = 5

(i) Let E be the event of getting a red ball

n(E) = No. of red balls = 3
n(S) = No. of total balls = 8

\therefore Probability of the ball drawn to be red = 
P = \frac{n(E)}{n(S)}
= \frac{3}{8}

Posted by

HARSH KANKARIA

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