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  • A boy is moving on a straight road against a frictional force of 5 N. After travelling a distance of 1.5 km he forgot the correct path at a round-about of radius 100 m.

A boy is moving on a straight road against a frictional force of 5 N. After traveling a distance of 1.5 km he forgot the correct path at a roundabout of radius 100 m. However, he moves on the circular path for one and half cycles and then he moves forward up to 2.0km. Calculate the work done by him. 

 

Answers (1)

Explanation:-

The boy has to apply force in the direction of its motion against frictional force. Therefore, the angle between force and displacement will always be 0^{\circ}. To calculate the work done, we have to multiply the force by the distance travelled by the boy.
The magnitude of the force is always 5 Newton. The total distance travelled, will be equal to the sum of 3/2 times perimeter of the circular path and distance travelled along a straight track.

d=1500m+(3/2)(2\pi \times 100)m+2000m

d=4442m

Hence,

the work done formula as we know 

W = F . d

now, 

W=5\times 4442=22210J

Hence, the answer is 22210 J

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