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 A rocket is moving up with a velocity v. If the velocity of this rocket is suddenly tripled, what will be the ratio of two kinetic energies?

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Solution.

We know that kinetic energy is defined as:
KE=\frac{1}{2}mv^{2}
We can see that the kinetic energy will be proportional to the square of speed for a given body of constant mass.
As the rocket's speed is suddenly tripled, the rocket's kinetic energy will be nine times.
KE=\frac{1}{2}mv^{2}
\frac{KE_{i}}{KE_{f}}=\frac{V^{2}_{i}}{V^{2}_{f}}

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