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  • A boy is moving on a straight road against a frictional force of 5 N. After travelling a distance of 1.5 km he forgot the correct path at a round-about of radius 100 m.

A boy is moving on a straight road against a frictional force of 5 N. After travelling a distance of 1.5 km he forgot the correct path at a round-about of radius 100 m. However, he moves on the circular path for one and half cycle and then he moves forward upto 2.0km. Calculate the work done by him. 

 

Answers (1)

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Answer:   22210 J

Solution.

The boy has to apply force in the direction of its motion against frictional force.
Therefore, the angle between force and displacement will always be 0^{\circ}.
For calculating the work done, we have to multiply force with the distance travelled by the boy.
The magnitude of the force is always 5 newton.
Total distance travelled, will be equal to sum of 3/2 times perimeter of the circular path and distance travelled along a straight track.

d=1500m+(3/2)(2\pi \times 100)m+2000m

d=4442m

Hence work done:

W=5\times 4442=22210J

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