2.(iii)   A die is numbered in such a way that its faces show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws:

Probability -A die is numbered in such a way that its faces show
What is the probability that the total score is (iii) at least 6?

Answers (1)
+ 1 2 2 3 3 6
1 2 3 3 4 4 7
2 3 4 4 5 5 8
2 3 4 4 5 5 8
3 4 5 5 6 6 9
3 4 5 5 6 6 9
6 7 8 8 9 9 12

Total possible outcomes when two dice are thrown = 6\times6=36

Number of times when the sum is at least 6, which means sum is greater than 5 = 15

\therefore P(sum\ is\ atleast\ 6) = \frac{15}{36} = \frac{5}{12}

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