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A motorcyclist drives from A to B with a uniform speed of 30 km h^{-1} and returns back with a speed of 20 km h^{-1}. Find its average speed.

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The average speed is total distance travelled divided by total time taken.

Let the distance between A to B is X kilometre.

As it is moving with uniform speed, time taken from A to B will be  \frac{X}{30}.

Similarly time taken from B to A will be \frac{X}{20}.

Hence total time of motion will be \left ( \frac{X}{30} \right ) +\left (\frac{X}{20} \right )= \frac{X}{12}.

Total distance travelled will be equal to 2X.

Therefore, by dividing total distance by total time we can find average speed that would be 24 km/h.

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