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A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to  (a) H  (b) H1/2  (c) H  (d) H-1/2

Answers (1)

The answer is the option (d)
Velocity of freely falling body after falling from a height H is given b

y v= \sqrt{2gH}   

de-Broglie wavelength \lambda is given by

\lambda =\frac{h}{p}=\frac{h}{mv}\: or\: \frac{h}{m\sqrt{2gH}}

 where h, m and g are constant

  So,

\\\lambda \alpha \frac{1}{\sqrt{H}}\\ \lambda \alpha H^{-\frac{1}{2}}

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