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  • A raindrop of mass 1.00 g falling from a height of 1 km hits the ground with a speed of 50 m/s. Calculate a) the loss of PE of the drop

A raindrop of mass 1.00 g falling from a height of 1 km hits the ground with a speed of 50 m/s. Calculate

a) the loss of PE of the drop

b) the gain in KE of the drop

c) is the gain in KE equal to loss of PE? If not why?

Answers (1)

M = 0.001 kg

H = 1 km, v= 50 m/s, u =0

a) potential energy at highest point of drop

= mgh = 0.001 \times 10 \times 1000m = 10 J

b) Gain in kinetic energy

= \frac{1}{2} mv^{2} = \frac{1}{2} \times 0.001 \times 50 \times 50 = 1.25 J

c) as we can infer, the gain in KE is not equal to the loss in PE as there some energy lost due to resistance.

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infoexpert24

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