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  • An X-OR gate has following truth table: It is represented by following logic relation Y=bar{A}.B+A.bar{B} Build this gate using AND, OR and NOT gates.

 An X-OR gate has the following truth table:

A B Y
0 0 0
0 1 1
1 0 1
1 1 0

It is represented by following logical relation
Y=\bar{A}.B+A.\bar{B}
Build this gate using AND, OR, and NOT gates.

Answers (1)

Explanation:-

XOR can be obtained by combining two NOT gates, two AND gates, and one OR gate. The logic relation for the given table is as follows:

Y=\bar{A}.B+A.\bar{B}=Y_{1}+Y_{2}\\ when\: \: Y_{1}=\bar{A}.B \: \: and\: \: Y_{2}=A.\bar{B}

Y1 can be obtained as output of AND gate I for which one input is of A through NOT gate and another input is of B. Y2 can be obtained as output of AND gate II for which one input is of A and other input id of B through NOT gate.

Now Y can be obtained as output from OR where Y1 and Y2 are inputs of OR gate

Thus the logic circuit of this relation is given below

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infoexpert24

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