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In the circuit shown in Fig.14.14, when the input voltage of the base resistance is 10V, Vbe is zero and Vce is also zero. Find the values of Ib, Ic and \beta

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According to the problem V1 =10V, Resistance RB=400k\Omega, VBE=0, VCE=0 and Rc=3k\Omega


I_{B}=\frac{Voltage\: across\: R_{B}}{R_{B}}\\ =\frac{10}{400 \times 10^{3}}=25 \times 10^{-6}A=25\mu A

Voltage across RC=10V


I_{C}=\frac{Voltage\: across\: R_{C}}{R_{C}}\\ =\frac{10}{3\times 10^{3}}=3.33 \times 10^{-3}A=3.33mA\\ \beta =\frac{I_{C}}{I_{B}}=\frac{3.33 \times 10^{-3}}{25 \times 10^{-6}}\\ =1.33 \times 10^{2}=133


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