Get Answers to all your Questions

header-bg qa

In the circuit shown in Fig.14.14, when the input voltage of the base resistance is 10V, Vbe is zero and Vce is also zero. Find the values of Ib, Ic and \beta

Answers (1)

According to the problem V1 =10V, Resistance RB=400k\Omega, VBE=0, VCE=0 and Rc=3k\Omega

Vi-VBE=RBIB

I_{B}=\frac{Voltage\: across\: R_{B}}{R_{B}}\\ =\frac{10}{400 \times 10^{3}}=25 \times 10^{-6}A=25\mu A

Voltage across RC=10V

VCC-VCE=ICRC

I_{C}=\frac{Voltage\: across\: R_{C}}{R_{C}}\\ =\frac{10}{3\times 10^{3}}=3.33 \times 10^{-3}A=3.33mA\\ \beta =\frac{I_{C}}{I_{B}}=\frac{3.33 \times 10^{-3}}{25 \times 10^{-6}}\\ =1.33 \times 10^{2}=133

 

Posted by

infoexpert24

View full answer