Chlorophyll present in green leaves of plants absorbs light at 4.620 \times 10^{14}Hz. Calculate the wavelength of radiation in nanometer. Which part of the electromagnetic spectrum does it belong to?

Answers (1)

We know that

\lambda =\frac{c}{v}

For this problem,

C = 3 \times 10^{8} ms^{-1}

V= 4.620 \times 10^{14} Hz.

\lambda =3\times 10^{8}ms^{-1}/4.620\times 10^{14}Hz

=0.6494\times 10^{-6}m

Therefore, we can say that it belongs to the visible light of the spectrum

 

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