Which of the following sets of quantum numbers are correct?
n l m1
(i) 1 1 +2
(ii) 2 1 +1
(iii) 3 2 -2
(iv) 3 4 -2
The answer is the options (ii) and (iii)
As, in the case n = 1, then I ≠ 1, therefore option (i) is incorrect.
In case n = 3, I ≠ 4, therefore option (iv) is also incorrect.
In case, n = 2, I = 0, 1. When l = 1, then m = -1, 0, +1. Therefore option (ii) is correct.
In case n = 3, l= 0, 1, 2. When l = 2, m = -2, -1, 0, +1, +2. Therefore, option (iii) is also correct.