Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • D is any point on side AC of a Triangle ABC with AB equal to AC. Show that CD less than BD.

D is any point on side AC of an \triangleABC with AB = AC. Show that CD < BD.

Answers (1)

Given: ABC is a triangle and D is any point on AC.

AB = AC

To prove CD < BD.

Proof: In \triangleABC

AB = AC                                             (Given)

\angleABC = \angleACB                      (angles opposite to equal sides are equal)

In \triangleABC and \angleDBC

\angleABC > \angleDBC

\Rightarrow \angleACB > \angleDBC

\Rightarrow BD > CD                            (Side opposite to greater angle is larger)

\therefore CD < BD

Hence proved.

Posted by

infoexpert24

View full answer

Similar Questions

Latest Question