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  • In triangle ABC, AB = AC and angle B = 50^{\circ}. Then angle C is equal to (A) 40^{\circ} (B) 50^{\circ} (C) 80^{\circ} (D) 130^{\circ}

In △ABC,AB=AC and ∠B=50∘. Then ∠C is equal to
(A) 40∘
(B) 50∘
(C) 80∘
(D) 130∘

Answers (1)

Solution.        

We know that angles opposite to equal sides of a triangle are equal

AB=AC

 

Since ∠B is opposite to side AC and ∠C is opposite to side AB

∴∠B=∠C=50∘(∵∠B=50∘ given )

Hence option (B) is correct.

Posted by

infoexpert24

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