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  • In triangle ABC, AB = AC and angle B = 50^{\circ}. Then angle C is equal to (A) 40^{\circ} (B) 50^{\circ} (C) 80^{\circ} (D) 130^{\circ}

In \triangle ABC, AB = AC and \angle B = 50^{\circ}. Then \angle C is equal to
(A) 40^{\circ}\\ (B) 50^{\circ}\\ (C) 80^{\circ}\\ (D) 130^{\circ}\\

Answers (1)

[B] Solution.        

We know that angles opposite to equal sides of a triangle are equal

 AB = AC

Since, \angleB is opposite to side AC and \angleC is opposite to side AB

\therefore \angleB = \angleC = 50° (\because \angleB = 50° given)

Hence option (B) is correct.

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infoexpert24

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